Continuous and compounded interest?

I would appreciate any help with this problem.

3000 dollars is invested in a bank account at an interest rate of 6 per cent per year, compounded continuously. Meanwhile, 28000 dollars is invested in a bank account at an interest rate of 5 percent compounded annually.

To the nearest year, When will the two accounts have the same balance?

Thanks

Continuous and compounded interest?consolidation loans

For continuous interest remember: s=pe^(rt) where p is the intial amount, r is the rate, and t is time

For compound interest remember: s=p(1+i)^t where p is the initial amount, i is the interest rate, and t is time.

You have to set the s%26#039;s equal to each other and solve for the time.

pe^(rt)=p(1+i)^t

Put in your values:

3000e^(.06t)=28000(1.05)^t

Put like terms together:

[e^(.06t)]/[1.05^t]=28/3

Simplify:

[e^.06/1.05]^t=28/3

Take the ln of both sides:

t(ln(e^.06/1.05))=ln(28/3)

Solve for t:

t=ln(28/3)/(ln(e^.06/1.05))